Area of a right trapezoid with bases $15$ and $8$, and height $9$

Question

I can't figure out how they got that. I got 1080, they got 103.5. How???

Answer 1

Hint : area of Trapezoid is calculated by

$$ \frac{base_a + base_b}{2} \cdot height $$

Answer 2

As has been explained in comments, your formula doesn't work. Instead, split it up into two shapes. You have two shapes, a $7\times 9$ right-angled triangle, and an $8\times 9$ rectangle. Calculate their areas and the area of the trapezium is their sum.

Answer 3

Hint

Divide it into these polygons and determinate the areas separately. You might need to use the Pythagorean theorem.

If not, you might want to use the formula for the area of trapezoides:

$$\text{Area}=\frac{\text{base1}+\text{base2}}{2}·\text{height}$$