area of surface generated revolving about the x axis stuck

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Sorry, i'm sure this is an extremely simple problem, but stuck and extremely confused on how the answer is derived here

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I'm fine with getting the deriviate, and using the formula to find the area, but I just can't figure out how

we get sqrt(x/x-1) here

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and how multiplying these two, becomes the sqrt(x)

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step by step explanation would be amazing!! I appreciate your assistance!

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$f(x)$ is the punctual radius of the jar.

$2 \pi f(x)$ is the slice perimeter of the jar.

$\sqrt{1+f'(x)^2}dx$. This is esoteric. Ask your book, this is equal to $\sqrt{1+({dy\over dx})^2}dx=\sqrt{dx^2+dy^2}$. As you see, that is a little hypotenuse, for the length of the slice through the curve $f(x)$.

Hence the surface is the slice perimeter by its length, all sum: $$ \int 2 \pi f(x)\sqrt{1+f'(x)^2}dx $$

so... which is your function??