Im trying to find the area of $y^2=x^2(a^2-x^2)$ where $a>0$.
From my calculations it seems to be $$ 2\int_{0}^{a} x\sqrt{a^2 - x^2}dx=\frac{2}{3}a^3, $$ but I am not sure if it is right.
2026-03-29 03:45:13.1774755913
Area of $y^2=x^2(a^2-x^2)$
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