How do you prove that if $x>0$ then $arg(-x)=\pi -arctan(x)$. Geometrically this is clear. How would you prove it formally?
2026-05-05 15:58:12.1777996692
Argument of a complex number and negative
111 Views Asked by user643073 https://math.techqa.club/user/user643073/detail AtRelated Questions in COMPLEX-ANALYSIS
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