If we consider the two functions $\zeta (-3+it)$ and $\zeta(4+it)$, then according to the argument equation derived from the functional equation of the Riemann Zeta function
$Arg(\zeta(s))=Arg(\chi(s))+Arg(\zeta(1-s))$
and the equation of arguments of conjugate functions
$Arg(\zeta(\overline{1-s}))=Arg(\overline{\zeta(1-s)})=-Arg(\zeta(1-s))$
we obtain
$Arg(\zeta(s))-Arg(\chi(s))/2=-(Arg(\zeta(\overline{1-s}))-Arg(\chi(s))/2)$
then
1) in the coordinate system rotated by angle $-Arg(\chi(s))/2$ the angles of the vectors $\zeta (-3+it)$ and $\zeta (4+it)$ will be symmetric with respect to the axis rotated by angle $-Arg (\chi(s))/2$
2) in a fixed coordinate system $Arg (\zeta(4+it))\leq\varepsilon$, therefore in a moving coordinate system, the vectors $\zeta (-3+it)$ and $\zeta(4+it)$ will rotate in opposite directions, the vector $\zeta(-3+it)$ is clockwise, and the vector $\zeta(4+it)$ is counterclockwise
can we say that this rule holds for any values $\sigma<1/2$ for two functions $\zeta(\sigma+it)$ and $\zeta(1-\sigma+it)$ at any interval between the zeros of these functions (if they exist, because at the point of zero, perhaps $Arg(\zeta(\sigma+it))$ and $Arg(\zeta(1-\sigma+it))$ will have gaps)?
added 28.10
Is it possible to say something definite in this case about changing the module $\Delta|\zeta(s)_L|$, for example, if in the moving coordinate system $\pi<Arg(\zeta(s))<3\pi/4$ when $\sigma<1/2$, then $ \Delta|\zeta(s)_L|<0$, i.e. the module decreases, and if $\pi<Arg(\zeta(s))<\pi/2$ when $\sigma<1/2$, then $\Delta|\zeta(s)_L|>0$, i.e. the module increases?
Where $L$ is a line rotated by angle $-Arg(\chi(s))/2$ and $\zeta(s)_L$ is a vector of projection of $\zeta(s)$ on this line.
Because in this case in the moving coordinate system the vector $\zeta (s)$ rotates clockwise.