Argument Principle Application

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$f(z)=z^3e^z$ and $\Gamma$ be the circle $z=e^{i\theta}$ where $d\theta$ varies from $0$ to $4\pi$. Then find

$$\int_{\Gamma} \dfrac{f’(z)}{f(z)}dz.$$

I applied the argument principle and got the answer as $2\pi i\cdot(3-0)$

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No, not quite. Notice that $\Gamma$ winds twice around the origin.