If the 8th term of an AP is 36 and the 16th term is 68
Find: a) the first term. b) the common difference. c) The 20th term.
$$8^{th} term=a_1+7d=36\\16^{th} term=a_1+15d=68$$ It follows $$d=\frac{68-36}{8}=4$$ Hence $$a_1=36-7\cdot 4=8\\a_{20}=a_{16}+4\cdot4=68+16=84$$
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$$8^{th} term=a_1+7d=36\\16^{th} term=a_1+15d=68$$ It follows $$d=\frac{68-36}{8}=4$$ Hence $$a_1=36-7\cdot 4=8\\a_{20}=a_{16}+4\cdot4=68+16=84$$