Asymptotic expansion

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How to find the leading behaviour of $$\int_0^1\sqrt {p(1-p)} (p+a)^{-x} dp $$ To proceed with Laplace method, I substituted $(p+a)^{-x}$ as $e^{-x\ln(p+a)}$ Please help me to proceed. Is it right to Taylor expand the logarithmic term and approximate it?