Does $f \in o(g)$ imply $g \not\in O(f)$?
Thank you very much for your help!
Try for instance $f(x)=\ln x$ and $g(x)=x$. Then $f\in o(g)$. But $g\not\in O(f)$.
In general, if $g$ grows faster than $f$, then $g/f$ will "blow up".
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Try for instance $f(x)=\ln x$ and $g(x)=x$. Then $f\in o(g)$. But $g\not\in O(f)$.
In general, if $g$ grows faster than $f$, then $g/f$ will "blow up".