I know I can't average the % change but I'm having trouble coming up with weights for these numbers Here's Image Link .
Each combined row represents a group and the bottom rows are adding up R and P basically. I'm wondering how you can end up with 35.2 if you have 33, 21 and 21.7. I can't come up with weights. Is there a solution to this? Also the percentage is calculated using the following logic:
(8.36/6.29)-1=33.03 (13.04/10.71)-1=21.72 and so on so we get 33.03 21.72 and 21.78
Essentially, we have, for $i = 1, 2, 3$:
At the bottom, we also have
There is no particular reason to think that $F$ is any kind of weighted mean of the $F_i$. This is, I think, basically a variation of Simpson's Paradox.
Here's a simpler example with only two rows that illustrates the issue:
$$ \begin{array}{|c|c|c|c|} \hline P & R & R/P & \text{percent difference} \\ \hline 5 & 20 & 4 & \\ 6 & 30 & 5 & \frac{5-4}{4} = 25\% \\ \hline 1 & 10 & 10 & \\ 10 & 130 & 13 & \frac{13-10}{10} = 30\% \\ \hline 5+1 = 6 & 20+10 = 30 & 5 & \\ 6+10 = 16 & 30+130 = 160 & 10 & \frac{10-5}{5} = 100\% \\ \hline \end{array} $$
The seeming "paradox" in this example arises from a few properties of the data:
In your data, the first set of data has smaller ratios and a modest increase in scale, whereas the other two sets of data have larger ratios and more dramatic increases in scale. It's less stark than in the example I constructed, but that's more or less what's happening.