Find an equation for the given line in the form $ax +by =c$, where a, b, and c are integers with no factor common to all three and a ≥0.
Through $(-40, 35)$; parallel to $7x + 8y = 13$
I put that in slope intercept form. Then use the Point Slope Formula.
Every time I do a question likes this I always get $c>0$.
So my answer would end up being $7x + 8y = 75$. But the answer seems to always be
$7x + 8y = 0$.
If they gave me $4x + 3y = 14$ (I made this up)
I can put in $4x + 3y = 0$ and get a correct answer.
However when I work this out I NEVER get $ax + by = 0$
I always get $ax + by > 0 $
And that is has never been the correct answer. I've spent 1 1/2 hours now trying to figure this out and I'm sure it's something simple.
I'm going to work through a problem on here.
9x + 4y = 13 (-8, 18)
y = -9/4x + 13
y - 18 = -9/4x + (x -- 8)
y - 18 = -9/4x - 36
4y + 9x = 36 But for my answer I put 9x + 4y = 0 and it was correct.
Ty for the responses, I need some time to digest what was just given.
Given the equation $ax+by=c$ ( with $b \ne 0$) the slope of the straight line is $$ m=-\frac{a}{b} $$ so the slope of $7x+8y=13$ is $m=-\frac{7}{8}$.
A parallel line have the same slope $m$ so its equation has the form: $$ y=-\frac{7}{8}x+q \qquad (1) $$ and, using the coordinates of the point $P=(-40,35)$ you can find $q$:
$$ 35=-\frac{7}{8}(-40)+q \quad \Rightarrow \quad q=0 $$
if you want write the equation in the form $ax+by=c$ you can reorder $(1)$ and multiply for any number, e.g. $8$ to find $7x+8y=0$