Let $\mathcal{T}$ be a theory in a language $\mathcal{L}$. A model $M$ of $\mathcal{T}$ is existentially-closed if for every existential $\mathcal{L}$-formula $\varphi(\bar{x})$, every extension $N \supseteq M$, and tuple $\bar{m}\in M$ we have that $N\models \varphi(\bar{m})$ implies $M\models \varphi(\bar{m})$. I know that if $\mathcal{T}$ is inductive (i.e., the class of its models is closed under unions of embedding chains) every model of $\mathcal{T}$ can be extended to an existentially-closed model.
In the examples I've seen in class there is always a theory $\mathcal{T}^{ec}$ that axiomatizes existentially-closed models of $\mathcal{T}$ (e.g. algebraically closed fields, real closed fields, DLOs without endpoints, etc.)
Q1: Does $\mathcal{T}^{ec}$ always exist? Do we need to assume that $\mathcal{T}$ is inductive?
If the answer is positive then this would imply
P: Any structure elementarily equivalent to an existentially closed model would itself be an existentially closed model.
This leads me to my second question
Q2: If the answer to Q1 is negative, can I have some counterexamples to $P$?
For inductive theories $T$, $T$ has a model companion if and only if the class of existentially closed models of $T$ is elementary (axiomatized by a first-order theory). An inductive theory satisfying these equivalent conditions is called companionable. If $T$ is companionable, then the theory $T^{ec}$ of its existentially closed models is the unique model companion of $T$. See Section 8.3 of Model Theory by Hodges.
Some examples of inductive theories which are not companionable: