$Az=λz$ lead to $x(t) = c_1*e^{\lambda_1 t}z_1+c_2*e^{\lambda2 t} z_2+...+c_p*e^{\lambda_p t}z_p$ is a solution to $dx/dt=Ax$. Why?

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I'm studying a course in dynamical systems. It's a pretty much linear algebra intensive course, and it's been a while since I did that sort of things.

In it, they say that if vector $z$ satisfies $Az=\lambda z$, then $x(t) = c e^{\lambda t} z$ is a solution to $dx/dt = Ax$.

So far so good.

Further, they claim that if there are several solutions to the equation $Az = \lambda z$, that is $A z_1 = \lambda_1 z_1, A z_2 = \lambda_2 z_2, ... , A z_p = \lambda_p z_p$, then according to the superposition principle it follows that for all $c_1, c_2, ... , c_p$ the vector function $x(t) = c_1*e^{\lambda_1 t}z_1+c_2*e^{\lambda_2 t} z_2+...+c_p*e^{\lambda_p t}z_p$ is a solution to $dx/dt=Ax$. I don't understand this reasoning. Could anybody explain why it follows from the superposition principle. Tried all day get my head around it.

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Given your final expression for $x(t)$,

$\displaystyle\frac{dx}{dt}=c_1\lambda_1 e^{\lambda_1 t} z_1+ c_2\lambda_2 e^{\lambda_2 t} z_2+ ... + c_p\lambda_p e^{\lambda_p t} z_p$.

Given your immediately preceding expressions relating $A$, $z_1, \lambda_1$, $z_2, \lambda_2$ etc.,

$\displaystyle\frac{dx}{dt}=c_1 e^{\lambda_1 t} Az_1 + c_2 e^{\lambda_2 t} Az_2 + ... + c_p e^{\lambda_p t} Az_p = A(c_1 e^{\lambda_1 t} z_1 + c_2 e^{\lambda_2 t} z_2 + ... + c_p e^{\lambda_p t} z_p)=$

$=Ax$

So your superposed expression is a solution of $\displaystyle\frac{dx}{dt}=Ax$.