$A,B$ is square matrix. I have to prove that $B^2=B$ implies $rank(AB-BA)\leq rank(AB+BA)$
I know $(I-B)(AB+BA)=AB-BAB=(AB-BA)B$. But I'm not sure what to do next.
2026-04-06 19:32:53.1775503973
$B^2=B$ implies $rank(AB-BA) \leq rank(AB+BA)$
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