Let vectors $\vec A, \vec B$ represent the sides of a quadrilateral parallelogram.
$\vec B \times (\vec A \times \vec B) $
$= \vec A(\vec B \cdot \vec B) - \vec B(\vec B \cdot \vec A)$
$= B^2 \vec A - \vec B(\vec B \cdot \vec A)$
Is the last line typed above the simplest way to express the triple cross product when two of the three vectors are the same?
Or can I simplify it to:
$= B^2 \vec A - (\vec B \vec B \cdot \vec B \vec A)$
Please point me in the right direction. I could not find this "vector property" aka:
vector times ( vector dot vector)
anywhere online.