I am trying to come up with an equation that is able to estimate the magnitude of the velocity a ball after it travelled a certain distance in the $x-$direction.
I came across the following site here and want to incorporate drag into the equation.
In the article, it discusses $\overrightarrow{F_d}=-\frac{1}{2}\rho v C_d A \hat{v} $ which we can divide by $m$ to figure out the acceleration of the drag force $\overrightarrow{a_d}=\frac{\overrightarrow{F_d}}{m}=-\frac{1}{2m}\rho v C_d A \hat{v} $.
Does that mean the acceleration of the ball equals the following: $\overrightarrow{a}=\text{acceleration of drag}+\text{acceleration due to gravity}=-\frac{1}{2m}\rho v C_d A \hat{v} -g\hat{j}$? I'm just confused on the physics part of this calculation.