Basic Calculus question - square numbers

Question

I am new to calculus. I am stuck with this:

if

$x-\frac{5}{\sqrt{x}} = 26$

$x - 5\sqrt{x} = $ ?

Answer 1

From the first equation, for $\sqrt{x}=t$ we have: $$ t^3-26t-5=0 \iff (t+5)(t^2-5t-1)=0 $$

since $t=-5 \rightarrow \sqrt{x}=-5$ is not possible, we have only $$ t^2-5t-1=0 \iff x-5\sqrt{x}=1 $$