Show that $B = {p_1(t), p_2(t), p_3(t)}$, where$\\p_1(t)=t^2+t+1 \\p_2(t)=t^2+t+2 \\ p_3(t)=t^2+2t+1$,
is a basis for $P_2$.
What is $(t^2)_B$ $∈ R^3$?
I dont really get the second question here? can someone explain it to me and guide me step by step towards the solution?
You need to show these polynomials are linearly independent.$$\\p_1(t)=t^2+t+1 \\p_2(t)=t^2+t+2 \\ p_3(t)=t^2+2t+1$$
That is
$$ c_1(t^2+t+1) + c_2(t^2+t+2 )+c_3(t^2+2t+1)=0 \implies c_1=c_2=c_3=0$$
Then you have to find coefficients $c_1,c_2,c_3$ such that $$ c_1(t^2+t+1) + c_2(t^2+t+2 )+c_3(t^2+2t+1)=t^2$$
These coefficients are coordinates of $t^2$ with respect to the basis $B =\{p_1,p_2,p_3\}$