in Evan's PDE book (see pic below)
$D^2f$ being the hessian matrix and $\Delta f = Trace(D^2f)$
I can't see why the highlighted equality in green hold ?
for example if you take $f(x,y) = x^2+y^2$
$D^2f = 2I_d \implies \| D^2f \|_{\infty} = 2$
but $\Delta f = 4 > \| D^2f \|_{\infty} $
so is $\| D^2f \|_{L^{\infty}(\mathbb{R^n})}$ something totally different from $ \| D^2f \|_{\infty}$ ?
