Something that many early students, including myself, take for granted is that $$x^\frac{3}{2}=\sqrt{x^3}=(\sqrt{x})^3$$
but is this true? Is exponentiation "commutative" and does a fractional exponent mean the same thing as a root?
Something that many early students, including myself, take for granted is that $$x^\frac{3}{2}=\sqrt{x^3}=(\sqrt{x})^3$$
but is this true? Is exponentiation "commutative" and does a fractional exponent mean the same thing as a root?
On
In the reals it is true that $(a^b)^c=a^{bc}=(a^c)^b$. This works for all $a \gt 0$ and any real $b,c$, so fractions are included.
It is not true in the complex numbers because there are multiple roots of a number and you need to be careful to pick the correct one. We avoid the root sign in the complex field for that reason.
No, this is not true in general.
You could create pointless results like this. Take for example $\sqrt{-2}$ which is not definied in $\mathbb{R}$.
But we have that $\sqrt{(-2)^2}=\sqrt{4}=2$, while $(\sqrt{-2})^2$ does not make sense.