Bernoulli generator

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I'm new at these things. How will I use the generator

$B_n(z)=\frac{D}{e^D-1}z^n$ where $D= \frac{d}{dz}$ is differentiation with respect to $z$ and the fraction is expanded as a formal power series.

How will I let the operator $D$ act on $z^n$? D is defined as d/dz. I have the idea of expanding $exp$ as a power series and applying $z^n$ to both the numerator and denominator.

Sorry for asking a stupid question. I am not a math major and my math background is only on complex analysis, ODEs, linear algebra, and calculus.

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Expand $\frac{D}{e^D-1}$ as a formal series around the origin as

$$\frac{D}{e^D-1} = \sum_{k=0}^\infty a_n D^n.$$

Then apply this formal operator to $z^n$. You get a polynomial as only a finite number of derivatives are not vanishing.