Can anyone figure out how to prove that the $$\int_{\sqrt x}^x \frac{1}{\log^2(t)} dt = O\left(\frac{x}{\log^2(x)}\right)$$
2026-03-28 22:37:36.1774737456
Big-O Notation, integration, proof
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HINT: use $ (1/\log x)' = -1/(x\log^2 x) $ to "solve" the integral, then have a look at LogIntegral