I have $f(a, b) \in O(b - a)$ and $g(a) \in O(a)$.
Can I conclude that $f(a,b) + g(a) \in O(b)$?
What if $f(a, b) \in \Theta(b - a)$ and $g(a) \in \Theta(a)$?
I have $f(a, b) \in O(b - a)$ and $g(a) \in O(a)$.
Can I conclude that $f(a,b) + g(a) \in O(b)$?
What if $f(a, b) \in \Theta(b - a)$ and $g(a) \in \Theta(a)$?
Well, answering my own question:
$f(a, b) = b - 2\cdot a$ is in $O(b - a)$, and $g(a) = a$ is in $O(a)$.
$f(a, b) + g(a) = b - 2\cdot a + a = b - a$ which apparently $\notin O(b)$.
So obviously I cannot conclude as intended, but I am still curious how I can reason about $f(a, b) + g(a)$.