Boundedness of Liouville function sum

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I would like to prove that $|\sum_{n \leq x}\frac{\lambda(n)}{n}|$ < 2, where $\lambda$ is the Liouville function,and n is integral. I have shown ,using Divisor Sum Identities, that for $x \geq 1$,$ \sum_{n \leq x}\lambda(n)[\frac{x}{n}] =[\sqrt{x}]$,but cannot see how to proceed. `