How can I calculate following integral and prove equality using residue theorem?
$$\int_0^1 \frac{1}{\sqrt[n]{x^n -1}}dx = \frac{sin \frac{\pi}{n}}{\frac{\pi}{n}}$$
How can I calculate following integral and prove equality using residue theorem?
$$\int_0^1 \frac{1}{\sqrt[n]{x^n -1}}dx = \frac{sin \frac{\pi}{n}}{\frac{\pi}{n}}$$
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