Calculate B^2013 where B is P^-1AP

Question

Using A and P, denote B=P^-1AP and calculate B^2013

I'm unsure of where to go with this question.

I know it involves diagonalization, but I'm not sure how that even works.

A is \begin{bmatrix}1&0\\0&i\end{bmatrix}

P is \begin{bmatrix}2&1\\1&1\end{bmatrix}

I found the inverse of P:\begin{bmatrix}1&-1\\-1&2\end{bmatrix}

and the product P^-1AP is \begin{bmatrix}2-i&1-i\\2i-2&2i-1\end{bmatrix}

Thanks for any advice!