Calculate $\int_{-1}^{-ln2} 6$ $te^{-t} dt$ . Simplify your answer. Your answer should not have any $e$’s in it.

Question

Calculate $\int_{-1}^{-\ln2} 6te^{-t} \, dt$ . Simplify your answer. Your answer should not have any $e$’s in it.

My attempt

I took $t=u$ and then differentiated with respect to $x.$

$dt=du$

$$\int_{-1}^{-\ln2} 6ue^{-u} \,du$$

But, I am stuck, can anyone explain how to solve this

Answer 1

I think that you have to calculate $\int_{-1}^{-\ln2} 6te^{-t} \, dt$.

Integrate by parts !