$$\lim _{x\to \infty }\left(\frac{\left(4x-1\right)^3}{\sin\left(\frac{x^2}{4}\right)\log \left(1+3x\right)}\right)$$
Not getting how to get started with it.
$$\lim _{x\to \infty }\left(\frac{\left(4x-1\right)^3}{\sin\left(\frac{x^2}{4}\right)\log \left(1+3x\right)}\right)$$
Not getting how to get started with it.
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$\sin\left(\frac{x^2}{4}\right)$ goes back and forth between $+1$, $0$, and $-1$ forever. So putting that in the denominator means that your answer will bounce between $\pm\infty$ forever without settling on any specific number.