Calculate the area between the two curves $y=3x^2+x-8$ and $y=2x^2+3x$

Question

I'm having trouble solving this question. I know how to calculate the area between the curves but I'm unsure how to get the upper and lower limits.

Answer 1

Hint: you can calculate the area as $$\int_{-2}^{4}(2x^2+3x-(3x^2+x-8))x$$ The result should be $36$