I bough wooden logs (not the chocks, sorry) and want to check the total volume of wood (m³).
I measured top perimeter length (circumference), bottom perimeter length and length of the even log.
The log section isn't always looks like a perfect circle, sometimes it's have an oval shape or a complex shape, but never curved inside.
So i have a three numbers in cm: 67, 68, 38. I entered all the data to spreadsheet and stuck with the right formula.
What the formula to find the volume of the even log?
Thank you.

What you want, it appears to me,is a portion of a toroid or a cylinder but not a chock.
By one theorem of Pappu, the swept out volume by rotation of areas around a central axis equals cross section area times central length $L$.From perimeters we compute radius at each end and swept volume.
$$ R=67/(2\pi) = \,10.663 {\,cm}, r = 68/ (2 \pi) = 10.823 {\,cm},\, L = 38 {\,cm},\, Vol= \pi ((R+r)/2)^2 \,L $$
So,Volume
$$= 13778\, {cm}^{3}$$
EDIT1:
WE can also compute the volume as a frustum of a cone
$$ \dfrac{\pi L}{3}(R^2+r^2+R r) $$
which also gives approximately the same answer.