
Hey I'm trying to solve this problem and I'm stuck. The integral I'm using to solve this problem is the integral from $0$ to $4$ of $2{\pi}y(27 - (y + 2)^3)$ but the answer isn't correct. Can anyone help me?

Hey I'm trying to solve this problem and I'm stuck. The integral I'm using to solve this problem is the integral from $0$ to $4$ of $2{\pi}y(27 - (y + 2)^3)$ but the answer isn't correct. Can anyone help me?
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You want to find $\int_0^{1} 2\pi r(y)h(y)\;dy=\int_0^{1}2\pi y(32-((y+2)^3+5))\;dy$