I have the question "An egg falls from a nest 3.70m above the ground. Calculate its velocity when it hits the ground and the time it takes to fall".
I know that velocity V = acceleration (a) X time (t)
I also know that the acceleration in this case is gravity so 9.81 ms$^-2$.
However, there is no time given and so I do not know how to calculate the velocity of the egg once it has hit the ground.
Notice that the potential energy is given by:
$$\text{E}_\text{pot}=\text{m}\cdot\text{g}\cdot\text{h}\tag1$$
And the kinetic energy:
$$\text{E}_\text{kin}=\frac{\text{m}\cdot\text{v}^2}{2}\tag2$$
So, set those equal (conservation of energy):
$$\text{E}_\text{pot}=\text{E}_\text{kin}=\text{m}\cdot\text{g}\cdot\text{h}=\frac{\text{m}\cdot\text{v}^2}{2}\space\Longleftrightarrow\space\text{v}=\pm\sqrt{2\cdot\text{g}\cdot\text{h}}\tag3$$
So, for $\text{v}$ we will get:
$$\text{v}\approx\sqrt{2\cdot9.81\cdot3.70}=\sqrt{\frac{36297}{500}}\approx8.520211265\tag4$$
And the time it takes:
$$t\approx\frac{\sqrt{\frac{36297}{500}}}{9.81}=\sqrt{\frac{740}{981}}\approx0.868523065\tag5$$