Calculus 3 Integration Problem

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Suppose I have to evaluate the line integral of:

$\int_{c}xye^{yz}dy$

Where $c$ is parametrized by:
$x=t$, $y=t^2$, $z=t^3$, $0\leq t\leq1$

This gives me:

$\int_{0}^{1}2t^4e^{t^5}\sqrt{9t^4+4t^2+1} dt$

Correct so far? If so, I'm really stumped on how to integrate this, one idea I have is completing the square of the expression under the square root, but I'm not too sure.

Any help would be appreciated, thanks.

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Actually it is much simpler: $$ \int_{c}xye^{yz}dy=\int_{c}0\,dx+xye^{yz}dy+0\,dz=\int_{0}^{1}2t^4e^{t^5} dt. $$