Calculus: computation of $\sum \frac{2^i}{i!}$

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$$\sum_{i=0}^\infty \frac{2^i}{i!}$$

Would anyone mind telling me what is the answer? I know this may be a silly question but I would like to know.

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The Maclaurin expansion of $e^x$ is: $$e^x = \sum_{n=0}^\infty \frac{x^n}{n!}$$

So therefore: $$\sum_{i=0}^\infty \frac{2^i}{i!} = e^2 \approx 7.389$$