Calculus- Definite Integrals

Question

Suppose that $$\int_{-1}^1 f(x)dx=5$$ $$\int_{1}^4 f(x)dx=-2$$ $$\int_{-1}^4 h(x)dx=7$$ Find the value of $$\int_{-1}^4 (2f(x)+3h(x))dx$$

I understand how to find definite and indefinite integrals, but I'm not entirely sure how to even begin this problem.

Answer 1

HINT: Recall that $$\int_a^b g(x)dx+\int_b^c g(x)dx=\int_a^c g(x)dx$$ for any function $g$.

Answer 2

HINT

Recall that

$$\int_{-1}^4 (2f(x)+3h(x))dx=2\int_{-1}^4 f(x)dx+3\int_{-1}^4 h(x)dx$$

and

$$\int_{-1}^4 f(x)dx=\int_{-1}^1 f(x)dx+\int_{1}^4 f(x)dx$$