What is the second derivative of $h(x)=g(f(x))$ I was able to find the first derivative which is $h'(x)=g'(f(x))\cdot f'(x)$ I know for the second derivative we are going to need to use both the chain rule and product rule but I am unsure how
2026-04-11 22:02:13.1775944933
Calculus derivatives
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$$h(x)=g(f(x))$$ $$h'(x)=g'(f(x))\times f'(x)$$ $$h''(x)=g''(f(x))\times f'(x)\times f'(x) + g'(f(x))\times f''(x)$$ $$h''(x)=g''(f(x))\times (f'(x))^2 + g'(f(x))\times f''(x)$$