Calculus Integrals

Question

I found this problem, but I am not quite sure how to solve it. It says:

Express $\int \log(\log x)dx$ in terms of $\int \frac {1}{ \log x} dx$

Some help would be appreciated.

Answer 1

Integrate by parts: $$\int \log (\log x)dx = x\log(\log x)-\int\frac{1}{\log x}dx.$$