Calculus, percentage of an interval for which a function is increasing

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So I have a question that asks,

Given $f(x) = 7 + 10x ^ 3 - 5x ^ 4 - 2x ^ 5$ calculate the percentage of the interval $[-6, 4]$ on which $f(x)$ is increasing.

So from this I determined that I must differentiate $f(x)$ and determine the intervals for which $f(x)$ is increasing and decreasing. Then determine how many numbers of the interval $[-6, 4]$ $f(x)$ is increasing for and express this number as a ratio to how many numbers are in the interval and then convert this to a percentage.

So the derivative of

$$f(x) = -10x ^ 2(x + 3)(x - 1)$$

The inequality statements for which f(x) is increasing and decreasing are

$$x < - 3, f'(x) < 0$$ $$3 < x < 0, f'(x) > 0$$ $$0 < x < 1, f'(x) > 0$$ $$x > 1, f'(x) < 0$$

so from this I know that there are $2$ numbers for which $f(x)$ is increasing for and there are $11$ numbers in the interval because I'm including the $-6$ and $4$ so

$$\frac{2}{11} = \frac{x}{100} = 18.1818\%$$

So given

$$f(x) = 7 + 10x ^ 3 - 5x ^ 4 - 2x ^ 5$$

$f(x)$ is increasing for $18.1818\%$ of the interval $[-6 , 4]$.

Basically what I want to know is if my understanding of this question and my solution is correct? I have no idea how to check my work on the percentage part.

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Your derivative is positive on the intervals $(-3,0)$ and $(0,1)$. This constitutes a total length of $4$ out of the entire length of $10$. Therefore the answer is $40\%$.

Here is a little tool to help answer questions like these (over a single interval):

https://www.desmos.com/calculator/2kxnwwcjh1

The percentage will be $$\dfrac{\text{Area of green rectangle}}{\text{Area of entire rectangle}}$$