Calculus problem dealing with integrals and derivatives as well as position function$= s(t)$, velocity function$= v(t)$, and acceleration$= a(t)$

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All functions are continuous and s is twice differentiable Find the following:

  1. $\displaystyle\frac{d}{\mathrm dt}\int_t^{t^2} v(w)\,\mathrm dw$
  2. $\displaystyle\int_t^{t^2} v(w)\,\mathrm dw$
  3. $\displaystyle\frac{d^2}{\mathrm dt^2}\int_t^{t^2} v(w)\,\mathrm dw$
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Set

$$F(x) = \int_0^xv(y)dy$$ then

$$\int_t^{t^2} v(y)dy = F(t^2)-F(t)\implies \frac{d}{dt}\int_t^{t^2} v(y)dy = 2t F'(t^2)-F'(t) = 2tv(t^2) -v(t)$$