The normal at the point $A=(-1,2)$ on the curve $y=3-x^2$ meets the curve again at $B$, find:
(1) The equation of the normal at $A$ and
(2) The coordinates of $B$
(3) Find the coordinates of the point $C$ on the curve where the curve is parallel to the normal at $A$
1 and 2 I understand how to solve, the solution I need is for Q3, coordinates of point C on the curve where the curve is parallel to the normal..
Hint: The slope of your curve is given by $$f'(x)=-2x$$ for $x=-1$ we get $$m=-\frac{1}{2}$$ so the equation of our normal line is given by $$y=-\frac{1}{2}x+n$$
Plug the coordintes $$x=-1,y=2$$ into your equation and you will get $n$