Can a finite value for $\int_1^\infty \exp(x^2)\,dx$ be defined?

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Why should $$\int_1^{\infty}\exp(ix^2)dx,\int_1^{\infty}\exp(-ix^2)dx,\int_1^{\infty}\exp(-x^2)dx$$ converges but not: $$\int_1^{\infty}\exp(x^2)dx$$

Is there any way that assigns a value to $\int_1^{\infty}\exp(x^2)dx$ which is consistent with the three former? (similar to $1+2+3+...=-\frac{1}{12}$)

EDIT: By suggestions from Nate, I think I should point out that I'm interested in the analytical continuation of $z\rightarrow \int_1^{\infty}\exp(zx^2)dx$. Does it exist? Does it have application in other fields?

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Why? Because the integrands of the first two are oscillating trigonometric functions, whose positive parts cancel out their negative ones in such a way that the final result is finite. $~$ The third one is a powerfully decreasing, and therefore convergent, exponential function. The last one is a powerfully increasing exponential function, diverging towards infinity.