I'm working on the following problem:
Here's what I've done so far:
$$-2i_1+4i_2+i_3+0i_4=0$$
$$-i_1+0i_2+i_3+6i_4=-14$$
$$5i_1-2i_2-i_3+i_4=6$$
$$i_1+2i_2+6i_3-i_4=6$$
It can be seen that, when put in matrix form, the entire matrix isn't diagonally dominant.
So my question here is, can I still solve this matrix or do I have to reduce down to the echelon form? Help!
2026-04-20 06:15:20.1776665720
Can a matrix that is not diagonally dominant be solved by Gauss-Siedel iteration?
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1
Hint
Rearrange the equations so they are in diagonally dominant form before applying the Gauss-Seidel (G-S) Algorithm as shown in these notes.
After doing this, the system to solve using G-S is
$$\left( \begin{array}{cccc} 5 & -2 & -1 & 1 \\ -2 & 4 & 1 & 0 \\ 1 & 2 & 6 & -1 \\ -1 & 0 & 1 & 6 \\ \end{array} \right)\left( \begin{array}{c} i_1 \\ i_2 \\ i_3 \\ i_4 \\ \end{array} \right)\text{ = }\left( \begin{array}{c} 6 \\ 0 \\ 6 \\ -14 \\ \end{array} \right)$$
Performing the algorithm with a starting point of $I_0 = (0,0,0,0)^T$, after eleven iterations, it converges to the correct result of
$$i_1 = 2, i_2 = 1, i_3 = 0, i_4 = -2$$
Of course, they only want you to perform five iterations.