Can anyone help me with this calculus variational problem?

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I'm having some problem finding the optimal trajectory $y^*(t)$:

$$V(y)=\int_{0}^{3}(y'+40t^3y)dt$$ with $y(0)=2$ and $y(3)=y_3$, with $y_3$ varying.

Basically, when I apply the Euler-Lagrange equation, the result is: $$F_{y}-\frac{dF_{y'}}{dt}=40t^3-0=0$$

Which doesn't make sense to me.

Thank you very much.