Can the Bayes Theorem be interpreted as a master equation in detailed balance?

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The general Bayes' theorem is well known as:

$$P(X|Y) = \frac{P(Y|X) \cdot P(X)}{P(Y)} $$

where $P(X)$ a prior probability distribution (belief), and $P(Y)$ a data probability distribution (observation).

If we would write:

$$ P(X|Y)\cdot P(Y) = P(Y|X) \cdot P(X) $$

and interpret the conditional probabilities as transition probabilities in the context of master equations (first order Markov chains assumed) then:

$$ 0= w(Y|X) \cdot P(X) - w(X|Y)\cdot P(Y)$$

Looks like a typical master equation under the very condition of detailed balance, derived from:

$$\partial_tP(X) = w(Y|X) \cdot P(X) - w(X|Y)\cdot P(Y)$$

Question: Is this interpretation mathematically correct, namely to interpret the Bayes theorem as a stationary solution of a master equation in detailed balance? If its is correct, then please describe the corresponding Markov process; if it is not correct, then please explain why?

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I could meanwhile answer this question and like to reference the following article with a complete solution presented to this question; https://medium.com/@vaseghisam/1763-meets-1968-how-bayes-illumes-the-detailed-balance-in-chapman-and-kolmogorovs-equation-7fc48e68140a