Can we determine the divisibility of a polynomial by another polynomial from their roots?

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I had this small doubt. Is a polynomial divided by another polynomial if the set of roots of one polynomial is the subset of the set of roots of the other polynomial?

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There are two main points you forget to refer to -

  • multiplicity of a root - For example, $p(x)=x-1$ has a root $1$ with multiplicity $1$, but $p(x)=(x-1)^2$ has multiplicity $2$.

  • reducibility of the polynomial - For example, the polynomial $x^2+1$ is irreducible (and has no roots) over the real numbers.

You can fix your claim in the following manner -

If $p(x)$ and $q(x)$ are two polynomials such that:

  • both $p(x)$ and $q(x)$ are completely reducible to linear factors

  • every root of $p(x)$ is a root of $q(x)$, where the multiplicity in $q$ is higher

Then $p(x)$ is dividing $q(x)$.