Can we say any matrix whose quadratic form is $xy + z^2$ can be diagonalised to a Matrix who has two positive and one negative Eigen value?
If it can , from which theorem you can. I have been having a really bad time to understand one problem.
I would be highly obliged if anyone help me to get my doubt cleared.
Thank You in advance.
Yes it is possible by Sylvester's law of inertia since the matrix associated to $xy+z^2$ is
$$B=\begin{bmatrix}0&\frac12&0&0\\\frac12&0&0&0\\0&0&1&0\\0&0&0&0 \end{bmatrix}$$
with signature
$$n_+=2,n_-=1,n_0=1$$