Can you find integral of this function.

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Question:

Consider

$$F(x) = \frac{1}{\sin(x-a) \ \sin(x-b) \ \sin(x-c)}$$

Then, how to compute $\int F(x) \, \mathrm{d}x$?

Edit:

I have tried what I know about integral solving methods. I have tried doing it by parts taking second function as 1 it turned out to be a mess. I tried multiplying and dividing by constants having sin function in tricky ways but still a mess.

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Following @acchilehui's suggestion, take advantage of the fact:

$$\sin{(x-\theta)} = \sin{x}\cos{\theta} - \cos{x} \sin{\theta},$$

and make use of the Weierstrass substitution to write your integral as follows:

$$ I = \int \frac{2 \, \mathrm{d} t}{(2 t \, \cos{a} - (1-t^2) \, \sin{a})(2 t \, \cos{b} - (1-t^2) \, \sin{a})(2 t \, \cos{c} - (1-t^2) \, \sin{c})}. $$

It seems that the denominator can be nicely factorized up as follows (perhabps this is the tricky part):

$$\text{Den} = (t+\cot{a/2})(t+\cot{b/2})(t+\cot{c/2})(t-\tan{a/2})(t-\tan{b/2})(t-\tan{c/2})$$

so you can perform a partial fraction decomposition as follows:

$$ I = \int Q(t) \, \mathrm{d}t = \int \sum_i \frac{A_i}{t-t_i} \, \mathrm{d}t,$$

where $t_i$ are the roots of $\text{Den}$ and $A_i$ are given by (see here to see how it works):

$$A_i = \lim_{t\to t_i} Q(t)(t-t_i), $$

which leads to the solution

$$\color{blue}{I = \sum_i A_i \log{|t-t_i|}}$$

Substituting back $t = \tan{x/2}$ gives you the result in terms of $x$. Hope this helps!

Cheers.