Can you show that this equation can be derived from the relation $9\theta=-\sin 8\theta$, where $\theta = \frac{2\pi}{17}$ radians?

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It is known that the quantity $\cos \frac{2π}{17}$ is a root of the $8$'th degree equation, $$x^8 + \frac{1}{2} x^7 - \frac{7}{4} x^6 - \frac{3}{4} x^5 + \frac{15}{16} x^4 + \frac{5}{16} x^3 - \frac{5}{32} x^2 - \frac{x}{32} + \frac{1}{256} = 0$$ It is known that the regular $17$ sided polygon can be constructed from $cos \frac{2π}{17}$ , if this can be expressed in square roots. Can you show that this equation can be derived from the relation $9\theta=-\sin 8\theta$, where $\theta = \frac{2π}{17}$?

Can you demonstrate that it is possible to solve this particular $8$'th degree equation, even though there is no $8$'th degree formula? ( there is more than one possible form of solution; it is known that there is often more than one expression in radicals for the same quantity) Also, can you find a square root form for $\cos \frac{2\pi}{17}$ which has minimum number of terms?

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It is known that the quantity Cos 2π/17 radians is a root of the 8th degree equation, x8 + 1/2 x7 - 7/4 X6 - 3/4 X5 + 15/16 X4 + 5/16 X3 - 5/32 X2 - X/32 + 1/256 = 0 It is known that the regular 17 sided polygon can be constructed from Cos 2π/17 . If this can be expressed in square roots, can you show that this equation can be derived from the relation sin9θ=-sin 8θ. Where θ = 2π/17 radians? Can you demonstrate that it is possible to solve this particular equation algebraically, even though there is no 8th degree formula? (there is more than one possible form of solution; it is known that there is often more than one expression in square roots for the same quantity) Also, can you find a square root form for Cos 2π/17 which has a minimum number of terms? (*A reference for the 8th degree equation is: Wienstein, Eric, W, heptadecagon)