Is it possible to do some kind of simplifications on an expression like
$$ f : x, y \to \mathbb{R} \\ \frac{\frac{\partial^2 f}{\partial y^2}}{\frac{\partial f}{\partial y}} = \frac{\partial f}{\partial y} $$
So that $\frac{\partial f}{\partial y}$ in the denominator reduces $\frac{\partial^2 f}{\partial y^2}$ to $\frac{\partial f}{\partial y}$ like $\frac{a^2}{a}=a$, without knowing the function $f$.
I would say no, that's not allowed, but I'm just wondering.
Thank you.
$$\frac{\frac{\partial^2 f}{\partial y^2}}{\frac{\partial f}{\partial y}}=\frac{\frac{\partial}{\partial y}\left(\frac{\partial f}{\partial y}\right)}{\frac{\partial f}{\partial y}}\ne\frac{\partial f}{\partial y}$$
just as
$$ \frac{y^{\prime\prime}}{y^\prime}\ne y^\prime $$