Cardinal Inequality Exercise

Question

I'm reading a bit on set theory and there's this elementary question, but I just can't solve it
given the cardinal numbers $2 \le k \le \lambda$ and $\lambda$ is cardinal of an infinite set
prove that : $k^\lambda = 2^\lambda$
I appreciate it if you give me clues rather than directly answering it

Answer 1

Hint: use the inequality $\kappa^\lambda\leq (2^{\kappa})^{\lambda}$.